x^2+3x+1.25=0

Solution for x^2+3x+1.25=0 equation:

x^2+3x+1.25=0

a = 1; b = 3; c = +1.25;
Δ = b2-4ac
Δ = 32-4·1·1.25
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-2}{2*1}=\frac{-5}{2}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+2}{2*1}=\frac{-1}{2}
=-1/2
$